<?php function is_connected() { $connected = @fsockopen(“www.example.com”, 80); //website, port (try 80 or 443) if ($connected){ $is_conn = true; //action when connected fclose($connected); }else{ $is_conn = false; //action in connection failure } return $is_conn; } ?>
This seems to be what you’re looking for, it will attempt to return the full hostname if possible: http://us3.php.net/gethostbyaddr
This will tell if you’re connected to a network: ConnectivityManager connectivityManager = (ConnectivityManager)getSystemService(Context.CONNECTIVITY_SERVICE); boolean connected = (connectivityManager.getNetworkInfo(ConnectivityManager.TYPE_MOBILE).getState() == NetworkInfo.State.CONNECTED || connectivityManager.getNetworkInfo(ConnectivityManager.TYPE_WIFI).getState() == NetworkInfo.State.CONNECTED); Warning: If you are connected to a WiFi network that doesn’t include internet access or requires browser-based authentication, connected will still be true. You will need this permission in your manifest: <uses-permission … Read more
Almost all major browsers now support the window.navigator.onLine property, and the corresponding online and offline window events. Run the following code snippet to test it: console.log(‘Initially ‘ + (window.navigator.onLine ? ‘on’ : ‘off’) + ‘line’); window.addEventListener(‘online’, () => console.log(‘Became online’)); window.addEventListener(‘offline’, () => console.log(‘Became offline’)); document.getElementById(‘statusCheck’).addEventListener(‘click’, () => console.log(‘window.navigator.onLine is ‘ + window.navigator.onLine)); <button id=”statusCheck”>Click … Read more
Just use the plain function System.Net.NetworkInformation.NetworkInterface.GetIsNetworkAvailable() that return true of false if the connection is up. From MSDN: A network connection is considered to be available if any network interface is marked “up” and is not a loopback or tunnel interface. Keep in mind connectivity is not all, you can be connected to a local … Read more
That’s a perfectly reasonable approach to solving the problem. The bad thing is that you are really testing DNS rather than testing the whole network, but in practice you can often get by with treating those as equivalent. The other thing to remember, is that you will need to set a system property to turn … Read more
I did a little more research and I am updating my answer with a more current solution. I am not sure if you have already looked at it but there is a nice sample code provided by Apple. Download the sample code here Include the Reachability.h and Reachability.m files in your project. Take a look … Read more
public static bool CheckForInternetConnection(int timeoutMs = 10000, string url = null) { try { url ??= CultureInfo.InstalledUICulture switch { { Name: var n } when n.StartsWith(“fa”) => // Iran “http://www.aparat.com”, { Name: var n } when n.StartsWith(“zh”) => // China “http://www.baidu.com”, _ => “http://www.gstatic.com/generate_204”, }; var request = (HttpWebRequest)WebRequest.Create(url); request.KeepAlive = false; request.Timeout = timeoutMs; … Read more
The connectivity plugin states in its docs that it only provides information if there is a network connection, but not if the network is connected to the Internet Note that on Android, this does not guarantee connection to Internet. For instance, the app might have wifi access but it might be a VPN or a … Read more
You are right. The code you’ve provided only checks if there is a network connection. The best way to check if there is an active Internet connection is to try and connect to a known server via http. public static boolean hasActiveInternetConnection(Context context) { if (isNetworkAvailable(context)) { try { HttpURLConnection urlc = (HttpURLConnection) (new URL(“http://www.google.com”).openConnection()); … Read more