An email address must not exceed 254 characters. This was accepted by the IETF following submitted erratum. A full diagnosis of any given address is available online. The original version of RFC 3696 described 320 as the maximum length, but John Klensin subsequently accepted an incorrect value, since a Path is defined as Path = … Read more
You can use idxmax with axis=1 to find the column with the greatest value on each row: >>> df.idxmax(axis=1) 0 Communications 1 Business 2 Communications 3 Communications 4 Business dtype: object To create the new column ‘Max’, use df[‘Max’] = df.idxmax(axis=1). To find the row index at which the maximum value occurs in each column, … Read more
Where are MIN and MAX defined in C, if at all? They aren’t. What is the best way to implement these, as generically and type safe as possible (compiler extensions/builtins for mainstream compilers preferred). As functions. I wouldn’t use macros like #define MIN(X, Y) (((X) < (Y)) ? (X) : (Y)), especially if you plan … Read more
This is also possible without subquery: SELECT DISTINCT id ,max(round) OVER (PARTITION BY id) AS round ,first_value(score) OVER (PARTITION BY id ORDER BY round DESC) AS score FROM SCORES WHERE id IN (1,2,3) ORDER BY id; Returns exactly what you asked for. The crucial point is that DISTINCT is applied after window functions. SQL Fiddle. … Read more
We have an extension method to do exactly this in MoreLINQ. You can look at the implementation there, but basically it’s a case of iterating through the data, remembering the maximum element we’ve seen so far and the maximum value it produced under the projection. In your case you’d do something like: var item = … Read more
And you can add a max attribute that will specify the highest possible number that you may insert <input type=”number” max=”999″ /> if you add both a max and a min value you can specify the range of allowed values: <input type=”number” min=”1″ max=”999″ /> The above will still not stop a user from manually … Read more
Newer NumPy versions (1.8 and up) have a function called argpartition for this. To get the indices of the four largest elements, do >>> a = np.array([9, 4, 4, 3, 3, 9, 0, 4, 6, 0]) >>> a array([9, 4, 4, 3, 3, 9, 0, 4, 6, 0]) >>> ind = np.argpartition(a, -4)[-4:] >>> ind … Read more
max(stats, key=stats.get)
RFC 2616 (Hypertext Transfer Protocol — HTTP/1.1) states there is no limit to the length of a query string (section 3.2.1). RFC 3986 (Uniform Resource Identifier — URI) also states there is no limit, but indicates the hostname is limited to 255 characters because of DNS limitations (section 2.3.3). While the specifications do not specify … Read more
You are so close! All you need to do is select BOTH the home and its max date time, then join back to the topten table on BOTH fields: SELECT tt.* FROM topten tt INNER JOIN (SELECT home, MAX(datetime) AS MaxDateTime FROM topten GROUP BY home) groupedtt ON tt.home = groupedtt.home AND tt.datetime = groupedtt.MaxDateTime