How to get the index of a maximum element in a NumPy array along one axis
>>> a.argmax(axis=0) array([1, 1, 0])
>>> a.argmax(axis=0) array([1, 1, 0])
You can increment the stack depth allowed – with this, deeper recursive calls will be possible, like this: import sys sys.setrecursionlimit(10000) # 10000 is an example, try with different values … But I’d advise you to first try to optimize your code, for instance, using iteration instead of recursion.
Recent manuals say: The G++ minimum and maximum operators (‘<?’ and ‘>?’) and their compound forms (‘<?=’) and ‘>?=’) have been deprecated and are now removed from G++. Code using these operators should be modified to use std::min and std::max instead. A quick search of the past documents seems to indicate that they were removed … Read more
a.index(max(a)) will tell you the index of the first instance of the largest valued element of list a.
In C, the language itself does not determine the representation of certain datatypes. It can vary from machine to machine, on embedded systems the int can be 16 bit wide, though usually it is 32 bit. The only requirement is that short int <= int <= long int by size. Also, there is a recommendation … Read more
Let’s say you want to scale a range [min,max] to [a,b]. You’re looking for a (continuous) function that satisfies f(min) = a f(max) = b In your case, a would be 1 and b would be 30, but let’s start with something simpler and try to map [min,max] into the range [0,1]. Putting min into … Read more
max(alkaline_earth_values, key=lambda x: x[1]) The reason this works is because the key argument of the max function specifies a function that is called when max wants to know the value by which the maximum element will be searched. max will call that function for each element in the sequence. And lambda x: x[1] creates a … Read more
Resig to the rescue: Array.max = function( array ){ return Math.max.apply( Math, array ); }; Warning: since the maximum number of arguments is as low as 65535 on some VMs, use a for loop if you’re not certain the array is that small.
Say that you have a list values = [3,6,1,5], and need the index of the smallest element, i.e. index_min = 2 in this case. Avoid the solution with itemgetter() presented in the other answers, and use instead index_min = min(range(len(values)), key=values.__getitem__) because it doesn’t require to import operator nor to use enumerate, and it is … Read more
How about something like: SELECT mt.* FROM MyTable mt INNER JOIN ( SELECT id, MIN(record_date) AS MinDate FROM MyTable GROUP BY id ) t ON mt.id = t.id AND mt.record_date = t.MinDate This gets the minimum date per ID, and then gets the values based on those values. The only time you would have duplicates … Read more