I’ll try and break it down (example from documention) /* * The cellForRowAtIndexPath takes for argument the tableView (so if the same object * is delegate for several tableViews it can identify which one is asking for a cell), * and an indexPath which determines which row and section the cell is returned for. */ … Read more
Here’s a solution that works on each column successively using lapply(): as.data.frame(lapply(example,function(col) lookup$letter[match(col,lookup$number)])); ## a b c ## 1 A E A ## 2 B D D ## 3 C C C ## 4 D B B ## 5 E A E Alternatively, if you don’t mind switching over to a matrix, you can achieve … Read more
You can use 2 times cumsum(): # reset val desired_col #0 0 1 1 #1 0 5 6 #2 0 4 10 #3 1 2 2 #4 1 -1 -1 #5 0 6 5 #6 0 4 9 #7 1 2 2 df[‘cumsum’] = df[‘reset’].cumsum() #cumulative sums of groups to column des df[‘des’]= df.groupby([‘cumsum’])[‘val’].cumsum() print … Read more
You should use the excellent OpenCSV for reading and writing CSV files. To adapt your example to use the library it would look like this: public class ParseCSV { public static void main(String[] args) { try { //csv file containing data String strFile = “C:/Users/rsaluja/CMS_Evaluation/Drupal_12_08_27.csv”; CSVReader reader = new CSVReader(new FileReader(strFile)); String [] nextLine; int … Read more
This may be more generalizable to your situation in that you pass a list of indices. If speed is an issue (large data frame) I’d opt for lapply with do.call rather than sapply: x <- list(1:3, 4:6) do.call(cbind, lapply(x, function(i) rowMeans(dat[, i]))) Works if you just have col names too: x <- list(c(‘a’,’b’,’c’), c(‘d’, ‘e’, … Read more
You aren’t expected to alter the values attribute. Try df.columns.values = [‘a’, ‘b’, ‘c’] and you get: ————————————————————————— AttributeError Traceback (most recent call last) <ipython-input-61-e7e440adc404> in <module>() —-> 1 df.columns.values = [‘a’, ‘b’, ‘c’] AttributeError: can’t set attribute That’s because pandas detects that you are trying to set the attribute and stops you. However, it … Read more
We can do this in base R without doing any group by operation df$ID <- cumsum(!duplicated(df[1:2])) df # School Student Year ID #1 A 10 1999 1 #2 A 10 2000 1 #3 A 20 1999 2 #4 A 20 2000 2 #5 A 20 2001 2 #6 B 10 1999 3 #7 B 10 … Read more
You’re binding the ItemsSource to a property in the DataContext called Items, so to update the collection, you need to go to the Items property in the DataContext and clear it. In addition, the Items property needs to be of type ObservableCollection, not List if you want it to update the UI whenever the underlying … Read more
For a simpler solution, you can give the parent display: table and its children display: table-cell, like this: .parent { display: table; } .child { display: table-cell; } See DEMO. Please note that this does not work in IE7, so if IE7 support is required, a more elaborate solution would be needed.
Try the new CSS Grid Layout: grid-container { display: grid; /* 1 */ grid-auto-rows: 50px; /* 2 */ grid-gap: 10px; /* 3 */ grid-template-columns: repeat(auto-fill, minmax(30%, 1fr)); /* 4 */ } [short] { grid-row: span 1; /* 5 */ background-color: green; } [tall] { grid-row: span 2; background-color: crimson; } [taller] { grid-row: span 3; … Read more