How can I select rows in MySQL starting at a given row number?
I recommend working by obtaining the first page using: LIMIT 0, 10 then for the second page LIMIT 10, 10 then LIMIT 20, 10 for the third page, and so on.
I recommend working by obtaining the first page using: LIMIT 0, 10 then for the second page LIMIT 10, 10 then LIMIT 20, 10 for the third page, and so on.
The CouchDB Guide has a good discussion of pagination, including lots of sample code, here: http://guide.couchdb.org/draft/recipes.html#pagination Here’s their algorithm: Request rows_per_page + 1 rows from the view Display rows_per_page rows, store last row as next_startkey As page information, keep startkey and next_startkey Use the next_* values to create the next link, and use the others … Read more
JohnWowUs’ answer is great and helped me understand how to avoid the recursion effectively, but there were some points I was still confused about, so I’m posting my tweaked version. Summary: The individual pages are returned as a Single. Use a Flowable to stream each of the items contained in the pages. This means callers … Read more
There are 3 ways that I would suggest for pagination with a custom post wp_query. Unfortunately to this day there isn’t a lot of good information about this out there, or at least what is out there is unclear in some cases. Hopefully this helps! Note, you also did have the wp_reset_postdata() in the wrong … Read more
The following T-SQL stored procedure is a very efficient implementation of paging. THE SQL optimiser can find the first ID very fast. Combine this with the use of ROWCOUNT, and you have an approach that is both CPU-efficient and read-efficient. For a table with a large number of rows, it certainly beats any approach that … Read more
Good question! “How many is too many?” – that, of course, depends on your data size and performance requirements. I, personally, feel uncomfortable when I skip more than 500-1000 records. The actual answer depends on your requirements. Here’s what modern sites do (or, at least, some of them). First, navbar looks like this: 1 2 … Read more
For that you need to have server side change also. Server will accept fromIndex and batchSize in the API url as query param. let listUrlString = “http://bla.com/json2.php?listType=” + listType + “&t=” + NSUUID().UUIDString + “&batchSize=” + batchSize + “&fromIndex=” + fromIndex In the server response, there will be an extra key totalItems. This will be … Read more
You can use Array.prototype.slice and just supply the params for (start, end). function paginate(array, page_size, page_number) { // human-readable page numbers usually start with 1, so we reduce 1 in the first argument return array.slice((page_number – 1) * page_size, page_number * page_size); } console.log(paginate([1, 2, 3, 4, 5, 6], 2, 2)); console.log(paginate([1, 2, 3, 4, … Read more
You can do that by adding a check on where you’re at in the cellForRowAtIndexPath: method. This method is easy to understand and to implement : – (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { // Classic start method static NSString *cellIdentifier = @”MyCell”; MyCell *cell = [tableView dequeueReusableCellWithIdentifier:cellIdentifier]; if (!cell) { cell = [[MyCell alloc] initWithStyle:UITableViewCellStyleDefault … Read more
In Laravel 5.3+ use $users->links(‘view.name’) In Laravel 5.0 – 5.2 instead of $users->render() use @include(‘pagination.default’, [‘paginator’ => $users]) views/pagination/default.blade.php @if ($paginator->lastPage() > 1) <ul class=”pagination”> <li class=”{{ ($paginator->currentPage() == 1) ? ‘ disabled’ : ” }}”> <a href=”https://stackoverflow.com/questions/28240777/{{ $paginator->url(1) }}”>Previous</a> </li> @for ($i = 1; $i <= $paginator->lastPage(); $i++) <li class=”{{ ($paginator->currentPage() == $i) ? … Read more