In your code, i is a pointer and it is not initialized, so the memory location it points to is indeterminate. Next, you are attempting to dereference it in (*i)….., which, invokes undefined behavior. You need to allocate memory (i.e., make the pointer point to some valid memory location) before you can dereference the pointer.
Assuming foo is a simple POD user-defined type used in an array, those 2 statements are certainly not the same. As you may know, all the following has the same semantic meaning for the above context: *foo *(foo + 0) foo[0] 0[foo] If you take the 2 statements and substitute them with the 3rd form … Read more
Java’s pointers (so called by the language specification, while I believe Java programmers mostly know them as “references”) do not support pointer arithmetic. And Java has no way to do pointer arithmetic. If you want to do such low-level stuff in Java, one way is to use JNI (the Java Native Interface) to access code … Read more
argv is an array of pointers pointing to zero terminated c-strings. I painted the following pretty picture to help you visualize something about the pointers. And here is a code example that shows you how an operating system would pass arguments to your executable. You can call your executable via command line and add any … Read more
Look, you know how to declare an integer, char, and float, because you did that already. You also have to declare Pointers too: int* p1; // p1 is a Pointer-to-Integer. char* p2; // p2 is a Pointer-to-Char. float* p3; // p3 is a Pointer-to-Float. p1 = &integer; // Set p1 to point to a real … Read more