React Javascript Array Object [closed]
You need to parse that object with JSON.parse(string) first.
You need to parse that object with JSON.parse(string) first.
Your object structure is incorrect. You need to put 1 and 2 on the same level of object ob: const ob = { “1”: [{ “name”: “destination” }], “2”: [{ “name”: “destination” }] }; console.log(ob[‘1’]); console.log(ob[‘2’]);
1) You’re missing a closing bracket on the ReactDOM line: ReactDOM.render(<Main />, document.getElementById(‘root’)); 2) You need to call the function for it to work vanilla_JS() In this working example instead of logging to the console I’m returning a string: function Main() { const vanilla_JS = function() { return ‘testing’; } return ( <main> <div>{vanilla_JS()}</div> </main> … Read more
Just go to the React documentation : Components let you split the UI into independent, reusable pieces, and think about each piece in isolation.
It is hard to say what you call “complex platform”, React is a library, not a framework or a platform (maybe RN is), so I would not consider it as a complex. There are pretty much libraries which are using virtual DOM rendering, I have few options for you: Deku – a library for rendering … Read more
You need to bind this in your methods. By convention, this is done in the constructor. Examples can be found here.
PHP is handled server-side. You don’t need to worry about that 😛 HTML is client side and can’t be obfuscated because the client won’t be able to read it. As for JS, I would recommend something like this. EDIT: As for seeing if the code is running on an okay domain, use window.location.href in your … Read more
You can create your table using Table function and EachRow function. var headers=[‘heading1′,’heading2’]; var values=[[‘1′,’2’],[‘3′,’4’]]; var Table = (props) => { return ( <table className=”table”> <thead> <tr> {props.headers.map(header => <th>{header}</th>)} </tr> </thead> <tbody> {props.values.map(row => <EachRow row={row} />)} </tbody> </table> ); }; var EachRow = (props) => { return ( <tr> {props.row.map(val => <td>{val}</td>)} </tr> … Read more
You can check if an element exists prior to using push. Lots of ways to approach this, but an easy solution might be: Array.prototype.pushUnique = function pushUnique(item) { if (this.indexOf(item) === -1) { this.push(item); } } // Then use it… const arr = []; arr.pushUnique(“Family Practice”); // arr = [“Family Practice”] arr.pushUnique(“General Practice”); // arr … Read more