How to round to at most 2 decimal places, if necessary?
How to round to at most 2 decimal places, if necessary?
How to round to at most 2 decimal places, if necessary?
You want to do two things in single shot: Get the integer value if first digit after decimal is 0 Get the rounded value upto last 2 digits if its first digit after decimal is not 0. For second option you can use: newValue = Math.Round(value, 2) Now comes the first requirement: Once you get … Read more
One can use angular built-in pipe such as number {{value | number:’1.0-0′}} If one wants to have an implementation of it: @Pipe({name: ’round’}) export class RoundPipe { transform (input:number) { return Math.floor(input); } } Use in the template {{1,1 | round}} => 1 {{2,1 | round}} => 2 Another useful pipe is a round ten … Read more
Two issues: round(3,98.9898, 2) is code that you enter. Omit the comma yourself and your problem goes away. Otherwise give us more info about your problem. def round(x, n): return round(x, n) Even if you fix your function call, you’ll most likely end up with RuntimeError due to maximum recursion. Rename your function to something … Read more
The problem is that the numbers are being calculated to a higher precision. Try, =ABS(ROUND(K2, 2)*(ROUND(K11, 2)-ROUND(K10, 2))/ROUND(K13, 2)) Look into the ‘Precision as displayed’ option but be sure to understand all of the caveats before deciding to do it.
There is nothing unreliable about numpy’s behavior in the examples you show as compared to MATLAB, nor do any of the examples you show have anything to do with floating-point issues (with one exception). For the rounding behavior, MATLAB is the one doing it wrong here. Numpy is following the IEEE standard for rounding. The … Read more