SegFault after scanf?
scanf requires the addresses of the variables to be passed to it. Replace your scanf by scanf(“%d %d”,&hour,&min); You should be good to go.
scanf requires the addresses of the variables to be passed to it. Replace your scanf by scanf(“%d %d”,&hour,&min); You should be good to go.
scanf accepts a pointer to whatever you are putting the value in. In the first instance, you are passing a reference to the specific int at position i in your integer array. In the second instance you are passing the entire array in to scanf. In C, arrays and pointers are synonymous and can be … Read more
The first problem is that the scanf() reads two characters, but not the newline afterwards. That means your fgets() reads the newline and finishes. You are lucky your program is not crashing. You tell fgets() that it is getting an array of 35 characters, but rather than passing an array, you pass the character (not … Read more
Make sure the scanf discards the newline. Change it to: scanf(” %c”, &loop); ^
I was able to skip lines with scanf with the following instruction: fscanf(config_file, “%*[^\n]\n”); The format string matches a line containing any character including spaces. The * in the format string means we are not interested in saving the line, but just in incrementing the file position. Format string explanation: % is the character which … Read more
Because there’s no null terminator. In C a “string” is a sequence of continuous bytes (chars) that end with a sentinel character called a null terminator (‘\0′). Your code takes the input from the user and fills all 5 characters, so there’s no “end” to your string. Then when you print the string it will … Read more
The a modifier to scanf won’t work if you are compiling with the -std=c99 flag; make sure you aren’t using that. If you have at least version 2.7 of glibc, you can and should use the m modifier in place of a. Also, it is your responsibility to free the buffer.
It far better to use char buf[big_enough * 2]; fgets(buf, sizeof buf, stdin) to read the line and then parse it, perhaps with sscanf(buf, ” { [ %lf … and sscanf(buf, ” { %lf …. Yet if code is obliged to stay with scanf(): OP’s first scanf(” { [ %lf … consumes the ‘{‘ expected … Read more
There is none. Use a temp object as the size of _Bool is implementation dependent. #include <stdbool.h> #include <stdio.h> bool b; int temp; scanf(“%d”, &temp); b = temp;
You’re confusing the assignment operator = with the equals operator ==. Write this instead: if (battlechoice == 4) And so on. Some C programmers use “Yoda conditionals” to avoid accidentally using assignment in these cases: if (4 == battlechoice) For example this won’t compile, catching the mistake: if (4 = battlechoice)