This is easiest to do when using PDO, not mysqli, as your database API. Build the WHERE clause dynamically. My recommended approach is to push each condition onto an array, and then use implode() to concatenate all the conditions, connecting them with AND or OR as is your preference. $wheres = array(); $params = array(); … Read more
import numpy as np def find_nearest(array, value): array = np.asarray(array) idx = (np.abs(array – value)).argmin() return array[idx] array = np.random.random(10) print(array) # [ 0.21069679 0.61290182 0.63425412 0.84635244 0.91599191 0.00213826 # 0.17104965 0.56874386 0.57319379 0.28719469] value = 0.5 print(find_nearest(array, value)) # 0.568743859261
You can use a generator expression: >>> dicts = [ … { “name”: “Tom”, “age”: 10 }, … { “name”: “Mark”, “age”: 5 }, … { “name”: “Pam”, “age”: 7 }, … { “name”: “Dick”, “age”: 12 } … ] >>> next(item for item in dicts if item[“name”] == “Pam”) {‘age’: 7, ‘name’: ‘Pam’} If … Read more
The problem is that when you’re searching for something linearly through an array, you can’t know that it’s not found until you reach the end of the array. The code in the question reports “Not found” for every non-matching element, even though there may be other matching elements. The simple modification is to use a … Read more
Code: function search($array, $key, $value) { $results = array(); if (is_array($array)) { if (isset($array[$key]) && $array[$key] == $value) { $results[] = $array; } foreach ($array as $subarray) { $results = array_merge($results, search($subarray, $key, $value)); } } return $results; } $arr = array(0 => array(id=>1,name=>”cat 1″), 1 => array(id=>2,name=>”cat 2″), 2 => array(id=>3,name=>”cat 1″)); print_r(search($arr, ‘name’, … Read more
Quote: I’ve tried using this statement below to find an appropriate column based on what I think it should be named but it returned no results.* SELECT * from dba_objects WHERE object_name like ‘%DTN%’ A column isn’t an object. If you mean that you expect the column name to be like ‘%DTN%’, the query you … Read more
Here’s a vectorized approach inspired by this other post and generalized to cover non-zeros for all four directions – def justify(a, invalid_val=0, axis=1, side=”left”): “”” Justifies a 2D array Parameters ———- A : ndarray Input array to be justified axis : int Axis along which justification is to be made side : str Direction of … Read more
Well, this might be faster since it does the comparing in C: def occurrences(string, sub): count = start = 0 while True: start = string.find(sub, start) + 1 if start > 0: count+=1 else: return count
Concatenating the querysets into a list is the simplest approach. If the database will be hit for all querysets anyway (e.g. because the result needs to be sorted), this won’t add further cost. from itertools import chain result_list = list(chain(page_list, article_list, post_list)) Using itertools.chain is faster than looping each list and appending elements one by … Read more
Probably you have problem on the server side. Could you append your question with the code of DynamicGridData action which you currently use. The action should have filters as the parameter. Some parts of your current code are definitively wrong. For example jqGrid is the jQuery plugin. So the methods of jQuery will be extended … Read more