After great help from @Brenlla the code was modified to: def sigmoid(x, L ,x0, k, b): y = L / (1 + np.exp(-k*(x-x0))) + b return (y) p0 = [max(ydata), np.median(xdata),1,min(ydata)] # this is an mandatory initial guess popt, pcov = curve_fit(sigmoid, xdata, ydata,p0, method=’dogbox’) The parameters optimized are L, x0, k, b, who are … Read more
You’re confusing the cross-entropy for binary and multi-class problems. Multi-class cross-entropy The formula that you use is correct and it directly corresponds to tf.nn.softmax_cross_entropy_with_logits: -tf.reduce_sum(p * tf.log(q), axis=1) p and q are expected to be probability distributions over N classes. In particular, N can be 2, as in the following example: p = tf.placeholder(tf.float32, shape=[None, … Read more
This should do it: import math def sigmoid(x): return 1 / (1 + math.exp(-x)) And now you can test it by calling: >>> sigmoid(0.458) 0.61253961344091512 Update: Note that the above was mainly intended as a straight one-to-one translation of the given expression into Python code. It is not tested or known to be a numerically … Read more