The absolute simplest way to accomplish this, is with basename() echo basename(‘http://domain.com/artist/song/music-videos/song-title/9393903’); Which will print 9393903 Of course, if there is a query string at the end it will be included in the returned value, in which case the accepted answer is a better solution.
Today (2.5 years after this answer) you can safely use Array.forEach. As @ricosrealm suggests, decodeURIComponent was used in this function. function getJsonFromUrl(url) { if(!url) url = location.search; var query = url.substr(1); var result = {}; query.split(“&”).forEach(function(part) { var item = part.split(“=”); result[item[0]] = decodeURIComponent(item[1]); }); return result; } actually it’s not that simple, see the … Read more
Editor’s note: the approach below has serious security implications and, depending upon the version of jQuery you are using, may expose your users to XSS attacks. For more detail, see the discussion of the possible attack in the comments on this answer or this explanation on Security Stack Exchange. You can use the location.hash property … Read more
<script> var config=true; </script> <script src=”https://stackoverflow.com/questions/1017424/myscript.js”></script> You can’t pass variables to JS the way you tried. SCRIPT tag does not create a Window object (which has a query string), and it is not server side code.
Use the urllib.parse library: >>> from urllib import parse >>> url = “http://www.example.org/default.html?ct=32&op=92&item=98″ >>> parse.urlsplit(url) SplitResult(scheme=”http”, netloc=”www.example.org”, path=”/default.html”, query=’ct=32&op=92&item=98′, fragment=””) >>> parse.parse_qs(parse.urlsplit(url).query) {‘item’: [’98’], ‘op’: [’92’], ‘ct’: [’32’]} >>> dict(parse.parse_qsl(parse.urlsplit(url).query)) {‘item’: ’98’, ‘op’: ’92’, ‘ct’: ’32’} The urllib.parse.parse_qs() and urllib.parse.parse_qsl() methods parse out query strings, taking into account that keys can occur more than once … Read more
If the browser supports RFC 1808 Section 4, RFC 2396 Section 5.2, or RFC 3986 Section 5.2, then it will indeed use the page URL’s scheme for references that begin with “//”.
It turns out that Google Android ships with Apache HttpClient 4.0, and I was able to figure out how to do it using the “Form based logon” example in the HttpClient docs: https://github.com/apache/httpcomponents-client/blob/master/httpclient5/src/test/java/org/apache/hc/client5/http/examples/ClientFormLogin.java import java.util.ArrayList; import java.util.List; import org.apache.http.HttpEntity; import org.apache.http.HttpResponse; import org.apache.http.NameValuePair; import org.apache.http.client.entity.UrlEncodedFormEntity; import org.apache.http.client.methods.HttpGet; import org.apache.http.client.methods.HttpPost; import org.apache.http.cookie.Cookie; import org.apache.http.impl.client.DefaultHttpClient; import org.apache.http.message.BasicNameValuePair; … Read more
All the gory details can be found in the current RFC on the topic: RFC 3986 (Uniform Resource Identifier (URI): Generic Syntax) Based on this related answer, you are looking at a list that looks like: A-Z, a-z, 0-9, -, ., _, ~, :, /, ?, #, [, ], @, !, $, &, ‘, (, … Read more
I usually prefer .replace() to regular expressions when possible, since it’s often easier to read: http://jsfiddle.net/mblase75/z2jKA/2 $(“div”).click(function() { var bg = $(this).css(‘background-image’); bg = bg.replace(‘url(‘,”).replace(‘)’,”).replace(/\”/gi, “”); alert(bg); });
For the benefit of the community, since this thread is top on Google when searching for “url validator java“ Catching exceptions is expensive, and should be avoided when possible. If you just want to verify your String is a valid URL, you can use the UrlValidator class from the Apache Commons Validator project. For example: … Read more