Code to parse user agent string?
The get_browser() function has been available in PHP for quite a long a time. The PHP manual is free, can be downloaded in various formats and viewed online (with comments)
The get_browser() function has been available in PHP for quite a long a time. The PHP manual is free, can be downloaded in various formats and viewed online (with comments)
As per Basil Bourque’s comment, this is the updated answer for this question, taking into account the new API of Java 8: String myDateString = “13:24:40”; LocalTime localTime = LocalTime.parse(myDateString, DateTimeFormatter.ofPattern(“HH:mm:ss”)); int hour = localTime.get(ChronoField.CLOCK_HOUR_OF_DAY); int minute = localTime.get(ChronoField.MINUTE_OF_HOUR); int second = localTime.get(ChronoField.SECOND_OF_MINUTE); //prints “hour: 13, minute: 24, second: 40”: System.out.println(String.format(“hour: %d, minute: %d, second: … Read more
Do a replace first: parseFloat(str.replace(‘,’,’.’).replace(‘ ‘,”))
Swift 2.0+ Now with Swift 2.0 you can just use Float(Wage.text) which returns a Float? type. More clear than the below solution which just returns 0. If you want a 0 value for an invalid Float for some reason you can use Float(Wage.text) ?? 0 which will return 0 if it is not a valid … Read more
Today (2.5 years after this answer) you can safely use Array.forEach. As @ricosrealm suggests, decodeURIComponent was used in this function. function getJsonFromUrl(url) { if(!url) url = location.search; var query = url.substr(1); var result = {}; query.split(“&”).forEach(function(part) { var item = part.split(“=”); result[item[0]] = decodeURIComponent(item[1]); }); return result; } actually it’s not that simple, see the … Read more
How can I validate an email address using a regular expression?