NHibernate serialization has been treated a lot on stackoverflow. See: C# Castle ActiveRecord: How to elegantly (XML) serialize ActiveRecord objects? How do I serialize all properties of an NHibernate-mapped object? NHibernate and WCF Serialization(Unidirectional) JSON.NET and nHibernate Lazy Loading of Collections Which .NET JSON serializers can deal with NHibernate proxy objects? DTOs vs Serializing Persisted … Read more
This works public static T DeepClone<T>(this T a) { using (MemoryStream stream = new MemoryStream()) { DataContractSerializer dcs = new DataContractSerializer(typeof(T)); dcs.WriteObject(stream, a); stream.Position = 0; return (T)dcs.ReadObject(stream); } }
No. You can’t serialize an interface. Ever. It just told you that. An interface is nothing more than a description of a set of behaviors. It says nothing about the contents of an instance. In particular, although an instance of a class implementing an interface must implement all of its members, it will certainly have … Read more
It sounds like you’re more after just parsing rather than full XML serialization/deserialization. If you can use LINQ to XML, this is pretty easy: using System; using System.Linq; using System.Xml.Linq; public class Test { static void Main() { string xml = “<Ids><id>1</id><id>2</id></Ids>”; XDocument doc = XDocument.Parse(xml); var list = doc.Root.Elements(“id”) .Select(element => element.Value) .ToList(); foreach … Read more
Just for anyone else who runs into this problem; armed with the answer above and the example from MSDN I managed to resolve this issue using the following class: public static class XmlSerializerCache { private static readonly Dictionary<string, XmlSerializer> cache = new Dictionary<string, XmlSerializer>(); public static XmlSerializer Create(Type type, XmlRootAttribute root) { var key = … Read more
In the code you posted, the type of CustomerAddresses is IList<CustomerAdress>. That’s an interface. Like the error message says, you can’t serialize an interface.
You’ll need to indicate which namespaces each field requires by using Namespace of XmlElement attribute. This will allow you to associate a field with a particular namespace, but you’ll also need to expose a property on your class that returns type XmlNamespaceDeclarations in order to get the prefix association. See documentation and sample below: [XmlRoot(ElementName … Read more
The most reliable way is to declare an outermost DTO class: [XmlRoot(“myOuterElement”)] public class MyOuterMessage { [XmlElement(“item”)] public List<TestObject> Items {get;set;} } and serialize that (i.e. put your list into another object). You can avoid a wrapper class, but I wouldn’t: class Program { static void Main() { XmlSerializer ser = new XmlSerializer(typeof(List<Foo>), new XmlRootAttribute(“Flibble”)); … Read more
[XmlText], like so: using System; using System.Xml.Serialization; [Serializable, XmlRoot(“myElement”)] public class MyType { [XmlAttribute(“name”)] public string Name {get;set;} [XmlText] public string Text {get;set;} } static class Program { static void Main() { new XmlSerializer(typeof(MyType)).Serialize(Console.Out, new MyType { Name = “foo”, Text = “bar” }); } }
This is the solution outlined by Manoj: If you want to suppress serialization of a specific property Foo, but still be able to deserialize it, you can add a method public bool ShouldSerializeFoo() that always returns false. Example: public class Circle2 { public double Diameter { get; set; } public double Radius { get { … Read more