Use re.finditer: import re sentence = input(“Give me a sentence “) word = input(“What word would you like to find “) for match in re.finditer(word, sentence): print (match.start(), match.end()) For word = “this” and sentence = “this is a sentence this this” this will yield the output: (0, 4) (19, 23) (24, 28)
Couple of points: Misplaced return statement. Should be at end. if yes(): It is wrong. You want to compare function input with yes. It should be if s == ‘yes’:. Same for rest also. Since you have written function definition as def shut_down(s):, it is expecting one argument. You should pass one argument while calling … Read more
Time::HiRes::time() is the equivalent. If you don’t need partial seconds, you can simply use time(), though.
The way to do this is clearly documented here. Example: >>> myString = “subString1|substring2|subString3” >>> myString = myString.split(“|”) >>> print myString [“subString1”, “subString2”, “subString3”]
Your example input/output suggests that you are looking for a power set. You could generate a power set for a string using itertools module in Python: from itertools import chain, combinations def powerset(iterable): “powerset([1,2,3]) –> () (1,) (2,) (3,) (1,2) (1,3) (2,3) (1,2,3)” s = list(iterable) return chain.from_iterable(combinations(s, r) for r in range(len(s)+1)) print(list(map(”.join, powerset(‘abcd’)))) … Read more
You can use a generator expression within the sum function >>> sum(i**i for i in range(1,11)) 10405071317
Check this out. http://www.python-course.eu/python3_formatted_output.php fruit = “orange” say = “hey eating {0} is a good idea”.format(fruit) print(say)
While the classic for(;;) loop can be used for any iteration that you can imagine, your particular loop can be written more readably like this: namespace sv = std::views; for (int i : sv::iota(0, n-1) | sv::reverse) { // … } Here’s a demo. For completeness, here’s what a classic for(;;) loop would look like: … Read more
You must supply a user when you create a department. You can access the current user as request.user if you are in a view user = request.user or fetch any user from the database if you are testing in the shell user = User.objects.get(id=1) # get then create the department: department = Department(name=”test”, description=’test’, user=user, … Read more
Yes, It was added in version 2.5. The expression syntax is: a if condition else b First condition is evaluated, then exactly one of either a or b is evaluated and returned based on the Boolean value of condition. If condition evaluates to True, then a is evaluated and returned but b is ignored, or … Read more