Yeah, you can test for any
:
type IfAny<T, Y, N> = 0 extends (1 & T) ? Y : N;
type IsAny<T> = IfAny<T, true, never>;
type A = IsAny<any> // true
type B = IsAny<number> // never
type C = IsAny<unknown> // never
type D = IsAny<never> // never
The explanation for this is in this answer. In short, any
is intentionally unsound, and violates the normal rules of types. You can detect this violation because it lets you do something crazy like assign 0
to 1
.