Understand Arraylist IndexOutOfBoundsException in Android

by

java.util.ArrayList.throwIndexOutOfBoundsException: Invalid index 3,
size is 3

It means you have ArrayList which having 3 elements where you can get each element like 0,1,2 positions. And you are trying to read 4th element which does not exists into ArrayList.

java.util.ArrayList.throwIndexOutOfBoundsException: Invalid index 0,
size is 0

It means you have a empty ArrayList, and you are trying to read 1st element.

ArrayIndexOutOfBoundsException – Examples

An array-index out of bounds exception is a Java exception thrown due to the fact that the program is trying to access an
element at a position that is outside an array limit, hence the words “Out of bounds”. In other words, the program is trying to
access an element at an index that is outside the array bounds. To understand array bounds, let us consider the following diagram:

enter image description here

The picture above contains an array that consists of 7 elements. Each element in the array has its own index/position. In Java, an index always starts with
0 and ends with the length of the array -1. For example, the array above consists of 7 elements, therefore it’s indices start from 0 and end with 6 (7-1). Attempting
to access an element with an index less than 0 or more than 6 will cause Java to throw an ArrayIndexOutOfBoundsException.

Read more about ArrayIndexOutOfBoundsException – Examples, Causes & Fixes

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