unpacking function argument [duplicate]

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You are looking for the *args argument syntax:

>>> def foo(bar, baz, spam):
...     print bar, baz, spam
...
>>> arguments = [1, 2, 3]
>>> foo(*arguments)
1, 2, 3

When passing arguments to a callable, any expression preceded by a * asterix, is interpreted as a sequence of positional arguments, and expanded to be passed on as separate arguments to the called object (function, method, etc.).

For your example that would be:

func1(*func2(...))

There is a keyword equivalent using ** double asterixes (takes a mapping), and you can use the same syntax in function signatures too.

See the documentation on call expressions, and for the function signature mirror syntax, the documentation on function definitions.

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