What do strict types do in PHP?

From the Treehouse blog:

With PHP 7 we now have added Scalar types. Specifically: int, float,
string, and bool.

By adding scalar type hints and enabling strict requirements, it is
hoped that more correct and self-documenting PHP programs can be
written. It also gives you more control over your code and can make
the code easier to read.

By default, scalar type-declarations are non-strict, which means they
will attempt to change the original type to match the type specified
by the type-declaration. In other words, if you pass a string that
starts with a number into a function that requires a float, it will
grab the number from the beginning and remove everything else. Passing
a float into a function that requires an int will become int(1).

By default, PHP will cast values of the wrong type into the expected scalar type if possible. For example, a function that is given an integer for a parameter that expects a string will get a variable of type string.

Strict types disabled (eval):

<?php

  function AddIntAndFloat(int $a, float $b) : int
  {
      return $a + $b;
  }

  echo AddIntAndFloat(1.4, '2');
  /*
  * without strict typing, PHP will change float(1.4) to int(1)
  * and string('2') to float(2.0) and returns int(3)
  */

It is possible to enable strict mode on a per-file basis. In strict mode, only a variable of exact type of the type declaration will be accepted, or a TypeError will be thrown. The only exception to this rule is that an integer may be given to a function expecting a float. Function calls from within internal functions will not be affected by the strict_types declaration.

To enable strict mode, the declare statement is used with the strict_types declaration:

Strict types enabled (eval):

<?php declare(strict_types=1);

  function AddIntAndFloat(int $a, float $b): int
  {
      return (string) $a + $b;
  }

  echo AddIntAndFloat(1.4,'2');
  // Fatal error: Uncaught TypeError: Argument 1 passed to AddIntAndFloat() must be of the type int, float given
  echo AddIntAndFloat(1,'2');
  // Fatal error: Uncaught TypeError: Argument 2 passed to AddIntAndFloat() must be of the type float, string given

  // Integers can be passed as float-points :
  echo AddIntAndFloat(1,1);
  // Fatal error: Uncaught TypeError: Return value of AddIntAndFloat() must be of the type integer, string returned

Working example:

<?php

declare(strict_types=1);

function AddFloats(float $a, float $b) : float
{
    return $a+$b;
}

$float = AddFloats(1.5,2.0); // Returns 3.5

function AddFloatsReturnInt(float $a, float $b) : int
{
    return (int) $a+$b;
}

$int = AddFloatsReturnInt($float,1.5); // Returns 5

function Say(string $message): void // As in PHP 7.2
{
    echo $message;
}

Say('Hello, World!'); // Prints "Hello, World!"

function ArrayToStdClass(array $array): stdClass
{
    return (object) $array;
}

$object = ArrayToStdClass(['name' => 'azjezz','age' => 100]); // returns an stdClass

function StdClassToArray(stdClass $object): array
{
    return (array) $object;
}

$array = StdClassToArray($object); // Returns array

function ArrayToObject(array $array): object // As of PHP 7.2
{
    return new ArrayObject($array);
}

function ObjectToArray(ArrayObject $object): array
{
    return $object->getArrayCopy();
}

var_dump( ObjectToArray( ArrayToObject( [1 => 'a' ] ) ) ); // array(1 => 'a');

More Related Contents:

Leave a Comment Cancel reply