Why do two functions have the same address?

You need to cast to void *:

std::cout << (void*)(ftype*)f<A> << std::endl;
std::cout << (void*)(ftype*)f<B> << std::endl;

If you cast to a function pointer (or several other classes of non-void pointers), it will be interpreted as a bool by the operator<< for std::ostream (hence the 1).

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