Why in the code “456”+1, output is “56” [duplicate]

The string literal "25" is really a char array of type const char[3] with values {'2', '5', '\0'} (the two characters you see and a null-terminator.) In C and C++, arrays can easily decay to pointers to their first element. This is what happens in this expression:

"25" + 1

where "25" decays to &"25"[0], or a pointer to the first character. Adding 1 to that gives you a pointer to 5.

On top of that, std::ostream, of which std::cout is an instance, prints a const char* (note that char* would also work) by assuming it is a null-terminated string. So in this case, it prints only 5.

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