Why is a=4 evaluated as true but b=0 evaluated as false in an if condition?

by

In both C and C++ language, any non-zero value is treated as true. In if condition you are assigning 4 and 0 to a and b causing the value of expressions a = 4 and b = 0 to be 4 and 0 respectively.

More Related Contents:

  1. Segmentation Fault in a brief amount of code
  2. comments longer than one line
  3. How to write if condition in while loop to terminate it
  4. Why this C code makes infinite loop?
  5. Assignment makes pointer from integer without a cast and vice versa in c
  6. No out of bounds error
  7. Passing by reference in C
  8. returning a local variable from function in C [duplicate]
  9. How to do scanf for single char in C [duplicate]
  10. About Tentative definition
  11. Is errno thread-safe?
  12. How does an uninitiliazed variable get a garbage value?
  13. Difference between const & const volatile
  14. how to control popen stdin, stdout, stderr redirection?
  15. How to get MAC address of your machine using a C program?
  16. How to get 100% CPU usage from a C program
  17. What is the simplest way to write to stdout in binary mode?
  18. Makefile to compile multiple C programs?
  19. What does “control reaches end of non-void function” mean?
  20. Parenthesis surrounding return values in C
  21. What is Undefined Behaviour in C? [duplicate]
  22. Is it necessary to reset the fd_set between select system call?
  23. What’s the difference between array and &array?
  24. C restore stdout to terminal
  25. Printing pointers in C
  26. Find size of array without using sizeof
  27. How do I get tcsetpgrp() to work in C?
  28. How to compute 2⁶⁴/n in C?
  29. How to fgets() a specific line from a file in C?
  30. Where do malloc() and free() store allocated sizes and addresses?

Leave a Comment