Access to method pointer to protected method?

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You can take the address through D by writing &D::Foo, instead of &B::Foo.

See this compiles fine : http://www.ideone.com/22bM4

But this doesn’t compile (your code) : http://www.ideone.com/OpxUy

Why can I call a protected method but not take its address?

You cannot take its address by writing &B::Foo because Foo is a protected member, you cannot access it from outside B, not even its address. But writing &D::Foo, you can, because Foo becomes a member of D through inheritance, and you can get its address, no matter whether its private, protected or public.

&B::Foo has same restriction as b.Foo() and pB->Foo() has, in the following code:

void Bar() {
    B b;
    b.Foo();     //error - cannot access protected member!
    B *pB = this;
    pB->Foo();   //error - cannot access protected member!
  }

See error at ideone : http://www.ideone.com/P26JT

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