Constructor in class cannot be applied to given types

when you create a constructor for a class, there won’t be any default constructor created for that class. so if you extend that class and if the subclass tries to call the no-arg constructor of its super class then there will be an compile-time error.

to demonstrate:

class Parent {
  int i;
  public Parent(int i) {
    this.i=i;
  }
}

class Child extends Parent {
  int j;
  public Child(int i, int j) {
    super(i);
    this.j=j;
  }
  public Child(int j) {
    // here a call to super() is made, but since there is no no-arg constructor
    // for class Parent there will be a compile time error
    this.j=j;
  }
}

EDIT:

to answer your question do this, don’t assign the value arrLength to arr[] and check[] as arrLength would be 0 at that time.

so just declare them like this

int arr[];
boolean check[];

and in the constructor after you assign the input to arrLength put these statements.

arr = new int[arrLength];
check = new boolean [arrLength];