Convert alphabet letters to number in Python

What about something like this:

print [ord(char) - 96 for char in raw_input('Write Text: ').lower()]

ord
list comprehension
ASCII character codes

EDIT
Since you asked me to explain I will… though it has been explained pretty well in the comments already by [?].

Let’s do this in more that one line to start.

input = raw_input('Write Text: ')
input = input.lower()
output = []
for character in input:
    number = ord(character) - 96
    output.append(number)
print output

This does the same thing, but is more readable. Make sure you can understand what is going on here before you try to understand my first answer. Everything here is pretty standard, simple Python. The one thing to note is the ord function. ord stand for ordinal, and pretty much every high level language will have this type of function available. It gives you a mapping to the numerical representation of any character. The inverse function of ord is called chr.

chr(ord('x')) == 'x' # for any character, not just x.

If you test for yourself, the ordinal of a is 97 (the third link I posted above will show the complete ASCII character set.) Each lower case letter is in the range 97-122 (26 characters.) So, if you just subtract 96 from the ordinal of any lower case letter, you will get its position in the alphabet assuming you take ‘a’ == 1. So, ordinal of ‘b’ == 98, ‘c’ == 99, etc. When you subtract 96, ‘b’ == 2, ‘c’ == 3, etc.

The rest of the initial solution I posted is just some Python trickery you can learn called list comprehension. But, I wouldn’t focus on that as much as I would focus on learning to solve the problem in any language, where ord is your friend. I hope this helps.

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