You can use an IsoDateTimeConverter
and specify the DateTimeFormat
to get the result you want, e.g.:
MyObject obj = JsonConvert.DeserializeObject<MyObject>(jsonString,
new IsoDateTimeConverter { DateTimeFormat = "dd/MM/yyyy" });
Demo:
class Program
{
static void Main(string[] args)
{
string json = @"{ ""Date"" : ""09/12/2013"" }";
MyObject obj = JsonConvert.DeserializeObject<MyObject>(json,
new IsoDateTimeConverter { DateTimeFormat = "dd/MM/yyyy" });
DateTime date = obj.Date;
Console.WriteLine("day = " + date.Day);
Console.WriteLine("month = " + date.Month);
Console.WriteLine("year = " + date.Year);
}
}
class MyObject
{
public DateTime Date { get; set; }
}
Output:
day = 9
month = 12
year = 2013