Does calling clone() on an array also clone its contents?

clone() creates a shallow copy. Which means the elements will not be cloned. (What if they didn’t implement Cloneable?)

You may want to use Arrays.copyOf(..) for copying arrays instead of clone() (though cloning is fine for arrays, unlike for anything else)

If you want deep cloning, check this answer

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A little example to illustrate the shallowness of clone() even if the elements are Cloneable:

ArrayList[] array = new ArrayList[] {new ArrayList(), new ArrayList()};
ArrayList[] clone = array.clone();
for (int i = 0; i < clone.length; i ++) {
    System.out.println(System.identityHashCode(array[i]));
    System.out.println(System.identityHashCode(clone[i]));
    System.out.println(System.identityHashCode(array[i].clone()));
    System.out.println("-----");
}

Prints:

4384790  
4384790
9634993  
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1641745  
1641745  
11077203  
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