Find intersection of two nested lists?

by

You don’t need to define intersection. It’s already a first-class part of set.

>>> b1 = [1,2,3,4,5,9,11,15]
>>> b2 = [4,5,6,7,8]
>>> set(b1).intersection(b2)
set([4, 5])

More Related Contents:

  1. Removing duplicates in lists
  2. Python -Intersection of multiple lists?
  3. Deleting certain elements in a list [closed]
  4. Iterating over every two elements in a list [duplicate]
  5. What are the advantages of NumPy over regular Python lists?
  6. Remove all occurrences of a value from a list?
  7. How to check if all elements of a list match a condition?
  8. Check for presence of a sliced list in Python
  9. List of lists into numpy array
  10. Replace values in list using Python [duplicate]
  11. Pandas DataFrame to List of Dictionaries
  12. Add SUM of values of two LISTS into new LIST
  13. Splitting list based on missing numbers in a sequence
  14. Using an index to get an item
  15. Print LIST of unicode chars without escape characters
  16. Combining two lists and removing duplicates, without removing duplicates in original list
  17. Some built-in to pad a list in python
  18. Sort a list of lists with a custom compare function
  19. Python – sum values in dictionary
  20. Get unique values in List of Lists
  21. How to apply __str__ function when printing a list of objects in Python [duplicate]
  22. Filtering a list based on a list of booleans
  23. Convert list into a pandas dataframe
  24. Why does list ask about __len__?
  25. How to assign each element of a list to a separate variable? [duplicate]
  26. How to create a fix size list in python?
  27. python – get list of tuples first index?
  28. Find a value in a list [duplicate]
  29. Creating a list in Python- something sneaky going on?
  30. Rearranging list based on order of another list

Leave a Comment