Deleting certain elements in a list [closed]

by 

a = range(10)
a = filter(lambda n: n%2 != 0, a)

it will give you
[1, 3, 5, 7, 9]

As you can see, no more six (and the same will happen with any multiple of six)

then, if you delete multiples of three

a = filter(lambda n: n%3 != 0, a)

a will be [1, 2, 4, 5, 7, 8]

More Related Contents:

  1. Search list for number in range
  2. Identify groups of continuous numbers in a list
  3. Python 3 turn range to a list
  4. converting a list of integers into range in python
  5. Python range() and zip() object type
  6. Print a list in reverse order with range()?
  7. Python 3 range Vs Python 2 range
  8. Python IndexError: list index out of range
  9. Strange result when removing item from a list while iterating over it in Python
  10. How to combine lists? (Python) [duplicate]
  11. Split a Pandas column of lists into multiple columns
  12. How to check if all elements of a list match a condition?
  13. Check for presence of a sliced list in Python
  14. How to do a recursive sub-folder search and return files in a list?
  15. List of lists into numpy array
  16. Replace values in list using Python [duplicate]
  17. Add SUM of values of two LISTS into new LIST
  18. Splitting list based on missing numbers in a sequence
  19. Using an index to get an item
  20. Some built-in to pad a list in python
  21. Sort a list of lists with a custom compare function
  22. Python – sum values in dictionary
  23. Union of multiple ranges
  24. range over character in python
  25. Convert list into a pandas dataframe
  26. Why does list ask about __len__?
  27. How to assign each element of a list to a separate variable? [duplicate]
  28. Appending to list in Python dictionary [duplicate]
  29. Swap values in a tuple/list inside a list in python?
  30. Check list monotonicity

Leave a Comment