getting type T from IEnumerable

by 
IEnumerable<T> myEnumerable;
Type type = myEnumerable.GetType().GetGenericArguments()[0];

Thusly,

IEnumerable<string> strings = new List<string>();
Console.WriteLine(strings.GetType().GetGenericArguments()[0]);

prints System.String.

See MSDN for Type.GetGenericArguments.

Edit: I believe this will address the concerns in the comments:

// returns an enumeration of T where o : IEnumerable<T>
public IEnumerable<Type> GetGenericIEnumerables(object o) {
    return o.GetType()
            .GetInterfaces()
            .Where(t => t.IsGenericType
                && t.GetGenericTypeDefinition() == typeof(IEnumerable<>))
            .Select(t => t.GetGenericArguments()[0]);
}

Some objects implement more than one generic IEnumerable so it is necessary to return an enumeration of them.

Edit: Although, I have to say, it’s a terrible idea for a class to implement IEnumerable<T> for more than one T.

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