On Linux, multiple children terminating before you read a SIGCHLD
with signalfd()
will be compressed into a single SIGCHLD
. This means that when you read the SIGCHLD
signal, you have to clean up after all children that have terminated:
// Do this after you've read() a SIGCHLD from the signalfd file descriptor:
while (1) {
int status;
pid_t pid = waitpid(-1, &status, WNOHANG);
if (pid <= 0) {
break;
}
// something happened with child 'pid', do something about it...
// Details are in 'status', see waitpid() manpage
}
I should note that I have in fact seen this signal compression when two child processed terminated at the same time. If I did only a single waitpid()
, one of the children that terminated was not handled; and the above loop fixed it.
Corresponding documentation:
- http://man7.org/linux/man-pages/man7/signal.7.html “By contrast, if multiple instances of a standard signal are delivered while that signal is currently blocked, then only one instance is queued”
- http://man7.org/linux/man-pages/man3/sigwait.3p.html “If prior to the call to sigwait() there are multiple pending instances of a single signal number, it is implementation-defined whether upon successful return there are any remaining pending signals for that signal number.”