highlight the word in the string, if it contains the keyword

by

Try this:

preg_replace("/\w*?$keyword\w*/i", "<b>$0</b>", $str)

\w*? matches any word characters before the keyword (as least as possible) and \w* any word characters after the keyword.

And I recommend you to use preg_quote to escape the keyword:

preg_replace("/\w*?".preg_quote($keyword)."\w*/i", "<b>$0</b>", $str)

For Unicode support, use the u flag and \p{L} instead of \w:

preg_replace("/\p{L}*?".preg_quote($keyword)."\p{L}*/ui", "<b>$0</b>", $str)

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