You can do this by doing pd.DataFrame(col.tolist())
on that column:
In [2]: df = pd.DataFrame({'a':[1,2], 'b':[(1,2), (3,4)]})
In [3]: df
Out[3]:
a b
0 1 (1, 2)
1 2 (3, 4)
In [4]: df['b'].tolist()
Out[4]: [(1, 2), (3, 4)]
In [5]: pd.DataFrame(df['b'].tolist(), index=df.index)
Out[5]:
0 1
0 1 2
1 3 4
In [6]: df[['b1', 'b2']] = pd.DataFrame(df['b'].tolist(), index=df.index)
In [7]: df
Out[7]:
a b b1 b2
0 1 (1, 2) 1 2
1 2 (3, 4) 3 4
Note: in an earlier version, this answer recommended to use df['b'].apply(pd.Series)
instead of pd.DataFrame(df['b'].tolist(), index=df.index)
. That works as well (because it makes a Series of each tuple, which is then seen as a row of a dataframe), but it is slower / uses more memory than the tolist
version, as noted by the other answers here (thanks to denfromufa).