Here’s a general solution that will handle an arbitrary amount of dictionaries, with cases when keys are in only some of the dictionaries:
from collections import defaultdict
d1 = {1: 2, 3: 4}
d2 = {1: 6, 3: 7}
dd = defaultdict(list)
for d in (d1, d2): # you can list as many input dicts as you want here
for key, value in d.items():
dd[key].append(value)
print(dd)
Shows:
defaultdict(<type 'list'>, {1: [2, 6], 3: [4, 7]})
Also, to get your .attrib
, just change append(value)
to append(value.attrib)