How to print 5 consecutive lines after a pattern in file using awk [duplicate]

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Another way to do it in AWK:

awk '/PATTERN/ {for(i=1; i<=5; i++) {getline; print}}' inputfile

in sed:

sed -n '/PATTERN/{n;p;n;p;n;p;n;p;n;p}' inputfile

in GNU sed:

sed -n '/PATTERN/,+7p' inputfile

or

sed -n '1{x;s/.*/####/;x};/PATTERN/{:a;n;p;x;s/.//;ta;q}' inputfile

The # characters represent a counter. Use one fewer than the number of lines you want to output.

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