How to send data from HTML form to Google Spreadsheet using JavaScript?

May 4, 2023 by Tarik Billa

A simple spreadsheet contained web app example

$(function() {
        $('#btn1').click(validate);
        $('#txt4').val('');
        $('#txt3').val('');
        $('#txt2').val('');
        $('#txt1').val('')
      });
function validate()
{
    var txt1 = document.getElementById('txt1').value || ' ';
    var txt2 = document.getElementById('txt2').value || ' ';
    var txt3 = document.getElementById('txt3').value || ' ';
    var txt4 = document.getElementById('txt4').value || ' ';
    var a = [txt1,txt2,txt3,txt4];
    if(txt1 && txt2 && txt3 && txt4)
    {
      google.script.run
        .withSuccessHandler(setResponse)
        .getData(a);
        return true;
    }
    else
    {
      alert('All fields must be completed.');
    }
}

The entire example:

The HTML:

<!DOCTYPE html>
<html>
  <head>
    <base target="_top">
  </head>
  <body>
  <div id="data">
    <br />Text 1<input type="text" size="15" id="txt1" />
    <br />Text 2<input type="text" size="15" id="txt2" />
    <br />Text 3<input type="text" size="15" id="txt3" />
    <br />Text 4<input type="text" size="15" id="txt4" />
    <br /><input type="button" value="submit" id="btn1" />
  </div>
  <div id="resp" style="display:none;">
    <h1>Response</h1>
    <p>Your data has been received.</p>
  </div>
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
    <script>
      $(function() {
        $('#btn1').click(validate);
        $('#txt4').val('');
        $('#txt3').val('');
        $('#txt2').val('');
        $('#txt1').val('')
      });

      function setResponse(a)
      {
        if(a)
        {
          $('#data').css('display','none');
          $('#resp').css('display','block');
        }
      }

      function validate()
      {
        var txt1 = document.getElementById('txt1').value || ' ';
        var txt2 = document.getElementById('txt2').value || ' ';
        var txt3 = document.getElementById('txt3').value || ' ';
        var txt4 = document.getElementById('txt4').value || ' ';
        var a = [txt1,txt2,txt3,txt4];
        if(txt1 && txt2 && txt3 && txt4)
        {
          google.script.run
            .withSuccessHandler(setResponse)
            .getData(a);
            return true;
        }
        else
        {
          alert('All fields must be completed.');
        }
      }

      function loadTxt(from,to)
      {
          document.getElementById(to).value = document.getElementById(from).value;
      }

     console.log('My Code');
   </script>
  </body>
</html>

The Apps Script:

function getData(a)
{
  var ts = Utilities.formatDate(new Date(), "GMT-6", "yyyy-MM-dd' 'HH:mm:ss");
  a.push(ts);
  SpreadsheetApp.getActiveSpreadsheet().getSheetByName('Login').appendRow(a);
  return true;
}

function doGet()
{
  var html = HtmlService.createHtmlOutputFromFile('index');
  return html.setXFrameOptionsMode(HtmlService.XFrameOptionsMode.ALLOWALL)

}

My simple spreadsheet:

The good news is that you’re probably a lot better at using the Google Chrome debugger now than before you started.

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