Here is one way
substring("aabbccccdd", seq(1, 9, 2), seq(2, 10, 2))
#[1] "aa" "bb" "cc" "cc" "dd"
or more generally
text <- "aabbccccdd"
substring(text, seq(1, nchar(text)-1, 2), seq(2, nchar(text), 2))
#[1] "aa" "bb" "cc" "cc" "dd"
Edit: This is much, much faster
sst <- strsplit(text, "")[[1]]
out <- paste0(sst[c(TRUE, FALSE)], sst[c(FALSE, TRUE)])
It first splits the string into characters. Then, it pastes together the even elements and the odd elements.
Timings
text <- paste(rep(paste0(letters, letters), 1000), collapse="")
g1 <- function(text) {
substring(text, seq(1, nchar(text)-1, 2), seq(2, nchar(text), 2))
}
g2 <- function(text) {
sst <- strsplit(text, "")[[1]]
paste0(sst[c(TRUE, FALSE)], sst[c(FALSE, TRUE)])
}
identical(g1(text), g2(text))
#[1] TRUE
library(rbenchmark)
benchmark(g1=g1(text), g2=g2(text))
# test replications elapsed relative user.self sys.self user.child sys.child
#1 g1 100 95.451 79.87531 95.438 0 0 0
#2 g2 100 1.195 1.00000 1.196 0 0 0