How to take all but the last element in a sequence using LINQ?

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The Enumerable.SkipLast(IEnumerable<TSource>, Int32) method was added in .NET Standard 2.1. It does exactly what you want.

IEnumerable<int> sequence = GetSequenceFromExpensiveSource();

var allExceptLast = sequence.SkipLast(1);

From https://docs.microsoft.com/en-us/dotnet/api/system.linq.enumerable.skiplast

Returns a new enumerable collection that contains the elements from source with the last count elements of the source collection omitted.

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