How to urlencode a querystring in Python?

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Python 2

What you’re looking for is urllib.quote_plus:

safe_string = urllib.quote_plus('string_of_characters_like_these:$#@=?%^Q^$')

#Value: 'string_of_characters_like_these%3A%24%23%40%3D%3F%25%5EQ%5E%24'

Python 3

In Python 3, the urllib package has been broken into smaller components. You’ll use urllib.parse.quote_plus (note the parse child module)

import urllib.parse
safe_string = urllib.parse.quote_plus(...)

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