Java PriorityQueue with fixed size

by 
que.add(d);
if (que.size() > YOUR_LIMIT)
     que.poll();

or did I missunderstand your question?

edit: forgot to mention that for this to work you probably have to invert your comparTo function since it will throw away the one with highest priority each cycle. (if a is “better” b compare (a, b) should return a positvie number.

example to keep the biggest numbers use something like this:

public int compare(Double first, Double second) {
            // keep the biggest values
            return first > second ? 1 : -1;
        }

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