Literal initialization for const references

So you can write code like this:

void f( const string & s ) {

f( "foobar" );

Although strictly speaking what is actually happening here is not the literal being bound to a const reference – instead a temprary string object is created:

string( "foobar" );

and this nameless string is bound to the reference.

Note that it is actually quite unusual to create non-parameter reference variables as you are doing – the main purpose of references is to serve as function parameters and return values.

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