As Jakob Christensen noted, you can load any XAML you want using XamlReader.Load
. This doesn’t apply only for styles, but UIElement
s as well. You just load the XAML like:
UIElement rootElement;
FileStream s = new FileStream(fileName, FileMode.Open);
rootElement = (UIElement)XamlReader.Load(s);
s.Close();
Then you can set it as the contents of the suitable element, e.g. for
<Window x:Class="MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="Foo Bar">
<Grid x:Name="layoutGrid">
<!-- any static elements you might have -->
</Grid>
</Window>
you could add the rootElement
in the grid
with:
layoutGrid.Children.Add(rootElement);
layoutGrid.SetColumn(rootElement, COLUMN);
layoutGrid.SetRow(rootElement, ROW);
You’ll naturally also have to connect any events for elements inside the rootElement
manually in the code-behind. As an example, assuming your rootElement
contains a Canvas
with a bunch of Path
s, you can assign the Path
s’ MouseLeftButtonDown
event like this:
Canvas canvas = (Canvas)LogicalTreeHelper.FindLogicalNode(rootElement, "canvas1");
foreach (UIElement ui in LogicalTreeHelper.GetChildren(canvas)) {
System.Windows.Shapes.Path path = ui as System.Windows.Shapes.Path;
if (path != null) {
path.MouseLeftButtonDown += this.LeftButtonDown;
}
}
I’ve not tried switching XAML files on the fly, so I cannot say if that’ll really work or not.