Macro expansion and stringification: How to get the macro name (not its value) stringified using another macro?

(The standard disclaimer about not abusing the C preprocessor without a really good reason applies here.)

It’s certainly possible to do what you want to do. You need a STRINGIFY macro and a bit of macro indirection.

Typically, STRINGIFY is defined with one level of indirection, to allow the C preprocessor to expand its arguments before they undergo stringification. One implementation is:

/* The # operator converts symbol 'v' into a string */
#define STRINGIFY0(v) #v
#define STRINGIFY(v) STRINGIFY0(v)

However, you’ll find that this isn’t enough:

#define _ACD 5, 5, 5, 30
#define DEFAULT_NETWORK_TOKEN_KEY_CLASS   _ACD 
#define DEFAULT_NETWORK_TOKEN_KEY { DEFAULT_NETWORK_TOKEN_KEY_CLASS }

#define START_MSG STRINGIFY(DEFAULT_NETWORK_TOKEN_KEY_CLASS)
const char startMsg[] = START_MSG;

Here, STRINGIFY(DEFAULT_NETWORK_TOKEN_KEY_CLASS) expands to STRINGIFY0(5,5,5,30), and the C preprocessor complains that you’ve given STRINGIFY0 too many arguments.

The solution is to delay the expansion of _ACD so it only expands to 5,5,5,30 when you want it to. To do this, define it as a function-like macro:

#define _ACD() 5, 5, 5, 30

This way, _ACD will only be expanded when you “call” it: _ACD(). DEFAULT_NETWORK_TOKEN_KEY_CLASS will now expand to _ACD, and you have to expand it further by “calling” it: DEFAULT_NETWORK_TOKEN_KEY_CLASS().

The following code illustrates the solution:

#include <stdio.h>

#define STRINGIFY0(v) #v
#define STRINGIFY(v) STRINGIFY0(v)

#define _ACD() 5, 5, 5, 30
#define DEFAULT_NETWORK_TOKEN_KEY_CLASS   _ACD 
#define DEFAULT_NETWORK_TOKEN_KEY { DEFAULT_NETWORK_TOKEN_KEY_CLASS() }

#define START_MSG STRINGIFY(DEFAULT_NETWORK_TOKEN_KEY_CLASS)

const char startMsg[] = START_MSG;

int main(int argc, char** argv)
{
  printf("%s\n",startMsg);
  return 0;
}