Obtaining ExitCode using Start-Process and WaitForExit instead of -Wait

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There are two things to remember here. One is to add the -PassThru argument and two is to add the -Wait argument. You need to add the wait argument because of this defect.

-PassThru [<SwitchParameter>]
    Returns a process object for each process that the cmdlet started. By default,
    this cmdlet does not generate any output.

Once you do this a process object is passed back and you can look at the ExitCode property of that object. Here is an example:

$process = start-process ping.exe -windowstyle Hidden -ArgumentList "-n 1 -w 127.0.0.1" -PassThru -Wait
$process.ExitCode

# This will print 1

If you run it without -PassThru or -Wait, it will print out nothing.

The same answer is here: How do I run a Windows installer and get a succeed/fail value in PowerShell?

It’s also worth noting that there’s a workaround mentioned in the “defect report” link above, which is as following:

# Start the process with the -PassThru command to be able to access it later
$process = Start-Process 'ping.exe' -WindowStyle Hidden -ArgumentList '-n 1 -w 127.0.0.1' -PassThru

# This will print out False/True depending on if the process has ended yet or not
# Needs to be called for the command below to work correctly
$process.HasExited

# This will print out the actual exit code of the process
$process.GetType().GetField('exitCode', 'NonPublic, Instance').GetValue($process)

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