You could take an object for the wanted order.
var array = [{ code: "RED", value: 0 }, { code: "BLUE", value: 0 }, { code: "RED", value: 0 }, { code: "GREEN", value: 0 }, { code: "BLUE", value: 0 }, { code: "RED", value: 0 }, { code: "GREEN", value: 0 }, { code: "BLUE", value: 0 }],
order = { GREEN: 1, BLUE: 2, RED: 3 };
array.sort(function (a, b) {
return order[a.code] - order[b.code];
});
console.log(array);
.as-console-wrapper { max-height: 100% !important; top: 0; }
For unknow colors/values, you could use a default value with
0
, for sorting to top orInfinity
or as some suggest because of the ability for caculatingNumber.MAX_VALUE
for sorting to the end,- or any other value for sorting inbetween the other groups.
At last you could sort the special treated items with an other sorting part, chained with logical OR ||
.
var array = [{ code: "YELLOW", value: 0 }, { code: "BLACK", value: 0 }, { code: "RED", value: 0 }, { code: "BLUE", value: 0 }, { code: "RED", value: 0 }, { code: "GREEN", value: 0 }, { code: "BLUE", value: 0 }, { code: "RED", value: 0 }, { code: "GREEN", value: 0 }, { code: "BLUE", value: 0 }],
order = { GREEN: 1, BLUE: 2, RED: 3, default: Infinity };
array.sort(function (a, b) {
return (order[a.code] || order.default) - (order[b.code] || order.default) || a.code.localeCompare(b.code);
});
console.log(array);
.as-console-wrapper { max-height: 100% !important; top: 0; }