Sorting a dictionary with lists as values, according to an element from the list

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Here is one way to do this:

>>> sorted(myDict.items(), key=lambda e: e[1][2])
[('item2', [8, 2, 3]), ('item1', [7, 1, 9]), ('item3', [9, 3, 11])]

The key argument of the sorted function lets you derive a sorting key for each element of the list.

To iterate over the keys/values in this list, you can use something like:

>>> for key, value in sorted(myDict.items(), key=lambda e: e[1][2]):
...   print key, value
... 
item2 [8, 2, 3]
item1 [7, 1, 9]
item3 [9, 3, 11]

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