String-Date conversion with nanoseconds

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The result you are getting is absolutely right.

Let’s analyze this:

17.08.2012 05:35:19:7600000
  • 17: Day of month (17th)
  • 08: Month of year (August)
  • 2012: Year (2012)
  • 05: Hour of day (5am)
  • 35: Minute of hour (:35)
  • 19: Second of minute (:19)
  • 7600000: Milliseconds of second (7,600,000)

Now, the way the VM sees this is that you are declaring the time of day as 5:35:19am, then adding 7,600,000 milliseconds to it. 7,600,000 milliseconds = 7,600 seconds = 2 hours, 6 minutes, 40 seconds. 5:35:19am + 02:06:40 = 7:41:59am (and 0 milliseconds). This is the result you are getting. (It also appears that you are not setting the timezone properly, so the GMT string is 3 hours behind your result.)

If you want to retain the :7600000, to my knowledge this is not possible. As this can be simplified into seconds, the VM will automatically reduce it into the other time increments. The milliseconds (the SSSS) should be for storing values <1000.

I’d suggest you create a new SimpleDateFormat for your output; but remember that the milliseconds will be absorbed into the other times (since they are all stored as a single long in the Date object).

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