The difference in assignment operators is clearer when you use them to set an argument value in a function call. For example: median(x = 1:10) x ## Error: object ‘x’ not found In this case, x is declared within the scope of the function, so it does not exist in the user workspace. median(x <- … Read more
Yes, it’s subassignment in R using <- (or = or ->) that makes a copy of the whole object. You can trace that using tracemem(DT) and .Internal(inspect(DT)), as below. The data.table features := and set() assign by reference to whatever object they are passed. So if that object was previously copied (by a subassigning <- … Read more
Overview Why do we need the copy-and-swap idiom? Any class that manages a resource (a wrapper, like a smart pointer) needs to implement The Big Three. While the goals and implementation of the copy-constructor and destructor are straightforward, the copy-assignment operator is arguably the most nuanced and difficult. How should it be done? What pitfalls … Read more
Introduction C++ treats variables of user-defined types with value semantics. This means that objects are implicitly copied in various contexts, and we should understand what “copying an object” actually means. Let us consider a simple example: class person { std::string name; int age; public: person(const std::string& name, int age) : name(name), age(age) { } }; … Read more
As always with these questions, the JLS holds the answer. In this case §15.26.2 Compound Assignment Operators. An extract: A compound assignment expression of the form E1 op= E2 is equivalent to E1 = (T)((E1) op (E2)), where T is the type of E1, except that E1 is evaluated only once. An example cited from §15.26.2 […] the following code is … Read more