A str is an abstract sequence of Unicode code points; a bytes is a sequence of 8-bit numbers. Python 3 made the distinction between the two very clear and does not allow you to combine them implicitly. A str may have several valid encodings, and a bytes object may or may not be the encoding … Read more
One way would be to create a FileStream with the FileMode.Append creation mode. Opens the file if it exists and seeks to the end of the file, or creates a new file. This would look something like: public static void AppendAllBytes(string path, byte[] bytes) { //argument-checking here. using (var stream = new FileStream(path, FileMode.Append)) { … Read more
ret[0] = (byte)(x & 0xff); ret[1] = (byte)((x >> 8) & 0xff);
public byte getBit(int position) { return (ID >> position) & 1; } Right shifting ID by position will make bit #position be in the furthest spot to the right in the number. Combining that with the bitwise AND & with 1 will tell you if the bit is set. position = 2 ID = 5 … Read more
There are two problems: Int is a 64-bit integer on 64-bit platforms, your input data has only 32-bit. Int uses a little-endian representation on all current Swift platforms, your input is big-endian. That being said the following would work: let array : [UInt8] = [0, 0, 0, 0x0E] var value : UInt32 = 0 let … Read more
If I understand you correctly, this should do the trick. You’ll need add using System.IO at the top of your file if you don’t already have it. public bool ByteArrayToFile(string fileName, byte[] byteArray) { try { using (var fs = new FileStream(fileName, FileMode.Create, FileAccess.Write)) { fs.Write(byteArray, 0, byteArray.Length); return true; } } catch (Exception ex) … Read more
Why do C#’s bitwise operators always return int regardless of the format of their inputs? I disagree with always. This works and the result of a & b is of type long: long a = 0xffffffffffff; long b = 0xffffffffffff; long x = a & b; The return type is not int if one or … Read more
Although the arithmetic operators are defined to operate on any numeric type, according the Java language specification (5.6.2 Binary Numeric Promotion), operands of type byte and short are automatically promoted to int before being handed to the operators. To perform arithmetic operations on variables of type byte or short, you must enclose the expression in … Read more
(It is probably a bit late for the OP, but it might still be useful for others) Unfortunately Java does not support arrays with more than 231−1 elements. The maximum consumption is 2 GiB of space for a byte[] array, or 16 GiB of space for a long[] array. While it is probably not applicable … Read more
String str = “Your string”; byte[] array = str.getBytes();