See this response by Jack Klein (see original post): The original C standard (ANSI 1989/ISO 1990) required that a compiler successfully translate at least one program containing at least one example of a set of environmental limits. One of those limits was being able to create an object of at least 32,767 bytes. This minimum … Read more
You can use Enumerable.Take like: char[] array = yourStringVariable.Take(5).ToArray(); Or you can use String.Substring. string str = yourStringVariable.Substring(0,5); Remember that String.Substring could throw an exception in case of string’s length less than the characters required. If you want to get the result back in string then you can use: Using String Constructor and LINQ’s Take … Read more
The first is an initialization while the second is an assignment. Since arrays aren’t modifiable values in C you can’t assign new values to them. Mind you, you can modify array contents, you just can’t say fast_car = …. So the contents are modifiable, the arrays themselves are not. Using the same symbol = for … Read more
Strings of dynamic length are always a bit tricky with the C interaction. A possible solution is to use pointers. First a simple case, where you have to hand over a null-character terminated string to a C-Function. If you really pass the string only in, you have to ensure to finalize it with the c_null_char, … Read more
A string literal is a const char[] in C++, and may be stored in read-only memory so your program will crash if you try to modify it. Pointing a non-const pointer at it is a bad idea.
You can’t assign anything to an array variable in C. It’s not a ‘modifiable lvalue’. From the spec, ยง6.3.2.1 Lvalues, arrays, and function designators: An lvalue is an expression with an object type or an incomplete type other than void; if an lvalue does not designate an object when it is evaluated, the behavior is … Read more
You can do something similar when looking for a char in a String, by using the indexOf method to search the string. if (“aeiouAEIOU”.indexOf(aChar) != -1)
I believe the << operator recognizes it as a string. Casting it to a void* should work: cout << (void*)&p; std::basic_ostream has a specialized operator that takes a std::basic_streambuf (which basically is a string (in this case)): _Myt& operator<<(_Mysb *_Strbuf) as opposed to the operator that takes any pointer (except char* of course): _Myt& operator<<(const … Read more
To do this properly, what you want is the algorithm for working out the grapheme cluster boundaries, as defined in UAX 29. Unfortunately this requires knowledge of which characters are members of which classes, from the Unicode Character Database, and JavaScript doesn’t make that information available(*). So you’d have to include a copy of the … Read more
First scanf read the entered string and left behind \n in the input buffer. Next call to scanf read that \n and store it to character. Try this scanf (” %c”, &characte); // ^A space before %c in scanf can skip any number of white space characters. Program will not work for strings more than … Read more